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wheeto
Yes is the short answer to your question but here's the long hand answer:
U6 meter - 6m[SUP]3[/SUP]/hr of gas
Here's the maths wheeto:
Heat input = (Gas Rate x Calorific Value of gas)/3.6
or
(6 x 38.6)/3.6 = 64.33 kW/hr
A U6/E6 meter will therefore supply appliances up to the value of 64kW max guaranteed! Any more than that required for the property and you'll require a larger gas meter!
Thanks for the maths, but you still got the unit wrong ... it's 64kW, not kW/h.